Electrochemistry+Test+Review

This is the page for any review notes, sites, or questions regarding the Electrochemistry Test for this Friday. Good luck everyone!

Stephanie's Questions: 1. In the following reaction, which substance is the oxidizing agent? Zn(s)+2HCl(aq) → ZnCl2(aq)+H2(g) a)Zn(s)    b)H+ c)Cl- d)H+ and Cl-  2. Which of the following is NOT true about an electric cell? a) An electric cell has two electrodes and an electrolyte. b) The electrodes and electrolyte both act as conductors c) The cathode is negative and the anode is positive    d) Electrons move from the anode to cathode  3. Which is False? a) The strongest oxidizing agent present in a galvanic cell always undergoes a reduction at the cathode b) The strongest oxidizing agent present in an electrolytic cell always undergoes a reduction at the cathode c) The strongest reducing agent present in a cell always undergoes an oxidation at the anode. I think the answer should be D.    d)The strongest reducing agent present in a cell always undergoes an oxidation at the cathode.

  One morning, at 11:00am, young Michael Faraday was working in his lab, about to discover benzene, when he suddenly remembered that he needed to make a 125g gold ring for the queen by 6:00pm. With his equipment he is able to run a 9.0A current through molten AuCl3. If it takes his best friend Gandalph (DEAR GOD STEPH YOU SPELLED GANDALF WRONG!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!) 1h to forge a nice looking ring, will young Michael be able to make enough gold on time ?  <span style="font-family: 'Times New Roman'; font-size: 12pt; mso-ansi-language: EN-CA; mso-bidi-language: AR-SA; mso-fareast-font-family: 'Lucida Sans Unicode'; mso-font-kerning: .5pt;"> __ <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;">Givens   __ <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;">I=9.0A mAu=125g MAuCl3 =196.97g/mol Au3+ + 3e- --> Au(s) Eor=1.50V q on 1 mol e-=96 500C/mol e-  <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;"> <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;">mol=m/M =125g/196.97g/mol =0.6346mol <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;"> <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;">1molAu=3mole- 0.6346mol Au=1.904e- <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;"> <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;">1.904 x 96 500=183 736 I=C/t t=C/I =183 736/9.0 =20 415s =5.67h <span style="color: #0000ff; font-family: 'Comic Sans MS',cursive; font-size: 90%;"> <span style="color: #0000ff; font-family: 'Times New Roman'; font-size: 12pt; msoansilanguage: EN-CA; msobidifontfamily: Tahoma; msobidilanguage: AR-SA; msofareastfontfamily: 'Lucida Sans Unicode'; msofontkerning: .5pt;">Therefore, there is enough time!